Your vessel is underway on a course of...

Question 1 / 2066636ee928f7522a1c51a66b

Question 1 of 2066636ee928f7522a1c51a66b

Your vessel is underway on a course of 323.5°T at a speed of 16 knots. At 1945 a light bears 350°T. At 2010 the light bears 008.5°T. What will be your distance off when abeam of the light?

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Question 1 of 20

66636ee928f7522a1c51a66b

Your vessel is underway on a course of 323.5°T at a speed of 16 knots. At 1945 a light bears 350°T. At 2010 the light bears 008.5°T. What will be your distance off when abeam of the light?

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🔍 Key Concepts

• Running fix using bearings of a single object • Using course and speed to convert time run into distance run • Determining distance off abeam from changing true bearings

💭 Think About

• How can you sketch your ship’s track as a straight line and plot the two bearings from the same fixed light to form a running fix? • What distance does the vessel travel between 1945 and 2010 at 16 knots, and how does that distance relate to the geometry between the two bearings? • When you are exactly abeam of the light, what is the relative bearing from your ship to the light, and how can you use that to find the perpendicular distance from your track to the light?

✅ Before You Answer

• Convert the time interval (1945–2010) to hours and then to distance run at 16 knots before doing any plotting or calculations. • Carefully note whether the bearings given are true bearings from the ship to the light, not from the light to the ship, and keep them consistent on your plot. • After plotting, verify that the distance you read off as distance abeam is a perpendicular distance from your track to the light, not the slant range along a bearing.

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Question 1 of 20

Your vessel is underway on a course of 323.5°T at a speed of 16 knots. At 1945 a light bears 350°T. At 2010 the light bears 008.5°T. What will be your distance off when abeam of the light?

8.7 miles

3.3 miles

4.8 miles

6.7 miles

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Question 1 / 2066636ee928f7522a1c51a66b

Question 1 of 2066636ee928f7522a1c51a66b

Your vessel is underway on a course of 323.5°T at a speed of 16 knots. At 1945 a light bears 350°T. At 2010 the light bears 008.5°T. What will be your distance off when abeam of the light?

Back

Question 1 of 20

66636ee928f7522a1c51a66b

Your vessel is underway on a course of 323.5°T at a speed of 16 knots. At 1945 a light bears 350°T. At 2010 the light bears 008.5°T. What will be your distance off when abeam of the light?

No comments yet

Be the first to share your thoughts!

If the question has a related picture, it will appear here.

🔍 Key Concepts

• Running fix using bearings of a single object • Using course and speed to convert time run into distance run • Determining distance off abeam from changing true bearings

💭 Think About

✅ Before You Answer

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

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