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9:41

StudyScore: 83% 15/18

Question 1 of 1

You are reading the draft marks shown in the illustration. The top 2 inches of the 9 forward is visible above the water level, and the water level is four inches below the 10 aft. What is the mean draft?

📖 Answer B

Answer B (9′-6″) is correct: forward draft 9′-4″ and aft draft 9′-8″ average to 9′-6″ mean draft.

🔑 Key Facts

• Draft numerals (Roman or Arabic) are 6 inches high with 6 inches between whole-foot marks; the bottom of the numeral is the draft it indicates (USCG / standard practice).

• The top of a numeral is 6 inches above its bottom (top of the 9 = 9′-6″).

• Mean draft = $\dfrac{\text{forward} + \text{aft}}{2}$ ; convert to inches before averaging, then convert back to feet and inches.

• Phrases like “below the 10” refer to the bottom of that numeral unless the stem explicitly references the top.

🧭 Solution

Step 1

Label the marks on D032DG:

Bottom of 9 = 9′-0″ = 108 in; top of 9 = 9′-6″ = 114 in
Bottom of 10 = 10′-0″ = 120 in

Step 2

Forward: “Top 2 inches of the 9 … visible above the water” → waterline is 2″ below the top of the 9.

$9'-6" - 2" = 9'-4" = 112\ \text{in}$

Step 3

Aft: “Water level is four inches below the 10 aft” → 4″ below the bottom of the 10.

$10'-0" - 4" = 9'-8" = 116\ \text{in}$

Final Step

Mean draft in inches:

$\dfrac{112 + 116}{2} = 114\ \text{in} = 9'-6"$ → choice B.

❌ Why Other Answers Are Wrong

Option A (9′-10″): Treating the aft reading as 10′-4″ (adding 4″ below the 10 instead of subtracting from 10′-0″) and/or using 9′-6″ forward without subtracting the 2″ below the top of the 9 pushes the mean toward 9′-10″.

Option C (9′-4″): This is the forward draft only—you stopped after the bow reading and never averaged in the deeper aft end.

Option D (9′-2″): Misreading “2 inches of the 9 visible” as 9′-2″ draft ignores that the numeral is 6″ tall; the waterline is only 2″ below the top of the 9, not 2″ above the bottom of the 9.

💡 Takeaway

Anchor every reading to the bottom of the numeral for whole feet, use the 6-inch height for the top, convert to inches, average, then convert back. The classic trap is assuming the waterline sits at the visible numeral instead of below it.

9:41

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Engineering Practice Test

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1) The purpose of annealing any metal is to make the metal __________.
1. A) softer
2. B) smoother
3. C) tougher
4. D) harder
5eccef9bbacbc34ba4d45119
2) One cubic foot of salt water would equal approximately how many pounds?
1. A) 24
2. B) 44
3. C) 64
4. D) 84
5eccef9bbacbc34ba4d45164
3) The proper use of a flat chisel is for cutting __________.
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2. B) slots or keyways
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4. D) flat stock

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66636eeb28f7522a1c51bd32
1) BOTH INTERNATIONAL & INLAND A vessel at anchor will show which shape?
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2. B) cone
3. C) ball
4. D) double cone, apexes together
66636eeb28f7522a1c51ba7b
2) BOTH INTERNATIONAL & INLAND What is the duration of a "short blast" on the whistle?
1. A) 1 second
2. B) 4 to 6 seconds
3. C) 8 to 12 seconds
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66636eeb28f7522a1c51bc82
3) BOTH INTERNATIONAL & INLAND A towing light, according to the Rules, is which color?
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66636ee728f7522a1c518dbf
1) Which U.S. agency assigns an official number to a vessel?
1. A) American Bureau of Shipping
2. B) Treasury Department
3. C) Collector of Customs
4. D) Coast Guard
66636ee728f7522a1c51849f
2) When oily ballast has been pumped overboard, an entry must be made in which log?
1. A) Oil Record Book
2. B) Official Logbook
3. C) Deck rough log
4. D) Engine rough log
66636ee728f7522a1c517801
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3. C) Portage Bill
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5eccef9fbacbc34ba4d46735
4) Which document will describe lifesaving equipment located aboard your vessel?
1. A) Clearance Papers
2. B) Forecastle Card
3. C) Muster List ("Station Bill")
4. D) Certificate of Inspection
66636ee728f7522a1c517a35
5) Which is the easiest way to dock a right-hand, single-screw vessel?
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Your vessel is listing because of a negative GM. To lower G below M, which action should you take?

We displace 6,000 LT. If we press up a double bottom with 150 LT of ballast at Kg 2.0 ft, is GM positive? Show me the math.

What the CFR says

46 CFR 170.285 requires stability calculations to count the virtual rise in G from liquids in tanks, so free surface stays in the math.

Where the equation comes from

Take moments about the keel. The new KG is the weighted average of the ship and the ballast:

KG_{new}=\frac{W\cdot KG + w\cdot Kg}{W+w}

Step by step

Ship: $6{,}000 \times 21.10 = 126{,}600$ ft-LT
Ballast: $150 \times 2.0 = 300$ ft-LT
$KG_{new} = \dfrac{126{,}900}{6{,}150} = 20.63$ ft
Free surface: $FSC = \dfrac{0.55 \times 6{,}000}{6{,}150} = 0.54$ ft
$GM = 21.40 - 20.63 - 0.54 = \mathbf{0.23}$ ft → positive

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New 2027 USCG questions added

🔍 Draft numerals

💭 Nudge

✅ Before you answer

📖 Answer B

🔑 Key Facts

🧭 Solution

❌ Why Other Answers Are Wrong

💡 Takeaway

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UnluckyPenguins

bye guns of glory

neweezy91

Bishops Fish Ops

Justin Matthews

S. Café

Collin Olesen

Spencer Dereich

Peter F

1StSon OfTheSea

Deep six Darrel

roman hutson

🔍 Draft numerals

💭 Nudge

✅ Before you answer

📖 Answer B

🔑 Key Facts

🧭 Solution

❌ Why Other Answers Are Wrong

💡 Takeaway

Everything you need. Nothing you don’t.

Study offline

Detailed explanations

📖 Answer A

🔑 Key Facts

🧭 Solution

❌ Why Other Answers Are Wrong

💡 Takeaway

Realistic test mode

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Printable PDF practice tests

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Answers you can read

Cites the regulation

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