Your vessel is on a course of 207°T at 13...

Study

Question 1 of 2066636ee928f7522a1c51a5b1

Your vessel is on a course of 207°T at 13 knots. At 0539 a light bears 180.5°T, and at 0620 the light bears 162°T. At what time and at what distance off will your vessel be when abeam of the light?

Back

Question 1 of 20

66636ee928f7522a1c51a5b1

No comments yet

Be the first to share your thoughts!

If the question has a related picture, it will appear here.

🔍 Key Concepts

• Convert true bearings to relative bearings from your ship’s head (angle on the bow) using the vessel’s course 207°T • Use a running fix / relative motion triangle with two bearings to a fixed object and known distance run between them • Understand that "abeam" means the object lies 90° off your course line (on the beam) and how that looks on a sketch

💭 Think About

• First, find how many degrees off the bow the light is at 0539 and 0620. Are those angles increasing or decreasing, and what does that tell you about where you are relative to the light? • Compute the distance run between 0539 and 0620 at 13 knots. How can you use that known run and the two angles on the bow to construct a right‑triangle that gives the distance off at abeam? • When will the angle on the bow be 90°? From your triangle, how far along your track is that point from your 0620 position, and how long will it take to steam that at 13 knots?

✅ Before You Answer

• Make sure you correctly find the time difference between 0539 and 0620 and convert it to hours before multiplying by speed • Check that you’re using angles on the bow (relative to your course), not the raw true bearings, in any trigonometry or geometrical construction • Verify that your final answer’s time is later than 0620 and that the distance off is reasonable compared to the distance run between the two observed bearings

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

Quick actions

— No credit card needed