Your vessel displaces 564 tons. The existing deck cargo has a center of gravity of 1.5 feet above the deck and weighs 41 tons. If you load 22 tons of ground tackle with an estimated center of gravity of 2.5 feet above the deck, what is the final height of the CG of the deck cargo?
• Combined center of gravity (KG) for multiple weights on the same level (use moments: weight × vertical distance) • How to treat existing cargo and new cargo as separate weights with their own centers of gravity • Why the ship’s total displacement (564 tons) is NOT used when you are only asked for the CG of the deck cargo
• First, write the moment (W × GZ) of the existing deck cargo, then the moment of the new ground tackle; how do you combine those? • Once you sum the total weight of deck cargo and the total moment, what operation gives you the new combined CG height? • Check which terms in the problem are a distraction and which are actually used in the CG calculation.
• Be sure you only use the weights of the deck cargo pieces (41 tons and 22 tons) to find the deck cargo CG, not the 564‑ton displacement • Calculate each moment carefully: moment = weight × height above deck for each item • After summing moments and total weight, divide total moment by total deck‑cargo weight and compare your result to the closest choice.
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