Your ship of 12,000 tons displacement has a...

Question 1 / 2066636eec28f7522a1c51ccc5

Question 1 of 2066636eec28f7522a1c51ccc5

Your ship of 12,000 tons displacement has a center of gravity of 21.5 feet above the keel. You run aground and estimate the weight aground is 2500 tons. What would be the virtual rise in the center of gravity?

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🔍 Key Concepts

• virtual rise in G when a ship takes the ground (ground reaction acting at or near the keel) • treating the weight aground as if a weight were shifted vertically from the keel (K) up to the original center of gravity (G) • using the ratio of weight aground to total displacement to find how far G appears to move

💭 Think About

• How does putting part of the ship’s weight on the ground change the portion of weight still supported by buoyancy, and where does that new upward force act? • If the ship’s G is 21.5 ft above the keel, what is the maximum possible upward shift of G if all the weight were transferred to the keel—and then what fraction of that corresponds to only 2500 tons out of 12,000 tons? • Should the virtual rise in G be larger or smaller than the original KG of 21.5 ft? Use this to eliminate unreasonable answer choices.

✅ Before You Answer

• Be sure you are using the ratio of weight aground to the ship’s total displacement (not the remaining buoyant weight) in your calculation, unless your specific formula says otherwise. • Confirm that the lever arm you are using is from the keel (0 ft) up to the original G at 21.5 ft. • After computing, check that the virtual rise is less than 21.5 ft and that the numerical result is close to one of the options without extra rounding errors.

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Question 1 of 20

1.26 feet

3.80 feet

4.80 feet

5.66 feet

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Question 1 / 2066636eec28f7522a1c51ccc5

Question 1 of 2066636eec28f7522a1c51ccc5

Back

Question 1 of 20

66636eec28f7522a1c51ccc5

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🔍 Key Concepts

💭 Think About

✅ Before You Answer

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

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