You make good 097°T from your 0830 fix. With a westerly current of 1.2 knots, what engine speed will you have to turn for from your 0830 position in order to arrive abeam of Six Mile Reef Buoy "8C" at 1030?
• Effect of set and drift on course and speed made good • Relationship between time, speed, and distance for a 2-hour run • Difference between speed through the water (engine speed) and speed over ground
• From 0830 to 1030, how much time do you have, and how does that limit the distance you can travel over the ground? • If the current is setting you west at 1.2 knots, is it helping or hurting your progress along 097°T? How does that change the engine speed you need? • Once you know the required speed over ground along 097°T, how do you combine that with the current vector to find the necessary speed through the water?
• Compute the time interval correctly from 0830 to 1030 in hours and use ( \text{Speed} = \frac{\text{Distance}}{\text{Time}} ). • Measure or determine the ground distance from the 0830 position to the point abeam of Six Mile Reef Buoy "8C". • Use a current triangle (vector triangle): one side is current (1.2 kn westerly), one is your unknown engine speed (through the water), and the resulting side is the required speed over ground toward the buoy.
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