You have approximately 34 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 7.5 feet? (total displacement is 638 tons)
• Use the shift of center of gravity formula: vertical shift in G = (w × d) / Δ • Identify clearly: w (weight being shifted), d (vertical distance moved), and Δ (total displacement) • Keep all units consistent (tons for weight, feet for distance) and do the fraction carefully
• What fraction of the ship’s total displacement does the 34 tons of fish represent? • If that fraction of the displacement moves 7.5 feet, how far will the ship’s overall center of gravity move? • Is the resulting shift a small value (much less than 1 foot) or a large one, based on the relative size of 34 tons to 638 tons?
• Confirm you are using the correct formula: shift of G = (w × d) / Δ • Double-check that 638 tons is the total displacement and 34 tons is only the weight being moved, not the new displacement • After calculating, compare your result to the answer choices and check if it is reasonable in magnitude (a few tenths of a foot, not several feet)
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