You estimate the current at 2.0 mph. What is the speed over the ground?
⢠Speed over ground (SOG) is your actual speed across the earth, combining your speed through the water and the current ⢠Relationship: SOG = speed through water ¹ current (depending on whether current is helping or opposing) ⢠Unit consistency: both vessel speed and current must be in the same units (mph)
⢠Is the current in this situation helping your vessel (moving in the same direction) or opposing it (moving in the opposite direction)? ⢠If your vesselâs speed through the water were known, how would you combine it with a 2.0 mph current to get SOG? Add or subtract? ⢠Look at the answer choices: which ones look like they could be a âhelpedâ speed (faster than through the water) and which look like an âopposedâ speed (slower than through the water)?
⢠Be sure you are thinking about speed over ground, not speed through the water ⢠Confirm whether you should add or subtract the 2.0 mph based on current direction relative to your course ⢠Check that your final SOG is reasonable compared with the vesselâs speed through the water (it should be slightly higher or lower, not a huge change)
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