You are steaming at 22 knots and burning 319 barrels of fuel per day. You must decrease your consumption to 137 barrels per day. What must you reduce your speed to in order to burn this amount of fuel?
• Relationship between speed and fuel consumption for displacement vessels (fuel roughly proportional to the cube of speed). • Using ratios: new fuel rate vs old fuel rate, and how that relates to new speed vs old speed. • Converting daily fuel consumption into a usable proportion without needing hours, since both are "per day".
• How does fuel consumption change when you slightly reduce speed on a displacement vessel? Is it linear, squared, or roughly cubed with speed? • If fuel ∝ speed³, what equation relates old speed and fuel to new speed and fuel? How can you solve for the new speed using a ratio? • Once you get a theoretical speed, which multiple-choice option is closest to that value?
• Confirm you’re using fuel ratio = (new speed / old speed)³ (not squared, and not linear). • Carefully compute the fuel ratio: 137 ÷ 319, then take the cube root to find the speed ratio. • After calculating the new speed, re-check your arithmetic and compare with the nearest option given.
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