You are on course 035° T, speed 18.3 knots. At 0719 you see a buoy bearing 036° T at a range of 4.1. If you change course at 0725 to leave the buoy abeam to port at 1.0 mile, at what time will the buoy be abeam?
• Use relative motion: where is the buoy now vs. where you will be after the course change? • Convert time and speed in knots into distance in nautical miles using ( \text{Distance} = \text{Speed} \times \text{Time} ). • Understand what "abeam to port at 1.0 mile" means in terms of relative bearing (90°) and range.
• From 0719 to 0725, how far will you travel on course 035° T at 18.3 knots, and how does that change the geometry between you and the buoy? • After you alter course at 0725, how long will it take before the buoy is exactly 1.0 NM away on your port beam (90° to your course)? • Which answer choices are too early or too late, given your speed and the approximate distances involved?
• Convert minutes of time to hours correctly before multiplying by speed in knots. • Sketch the situation before and after the course change so you can visualize when the buoy becomes abeam to port at 1.0 NM. • Check that your final time is later than 0725 (the time of the course change) and that the implied distance run at your speed is reasonable for that time interval.
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