While steaming at 19.4 knots, your vessel consumes 392 barrels of fuel oil per day. In order to reduce consumption to 182 barrels of fuel oil per day, what is the maximum speed the vessel can turn for?
• Relationship between speed and fuel consumption (approximate cube law for displacement ships) • How to set up a ratio/proportion between old condition and new condition • Converting daily fuel consumption change into a speed change
• How does fuel consumption change when speed increases or decreases on a displacement vessel—linearly, by the square, or by roughly the cube? • If you know fuel is reduced from 392 to 182 barrels/day, what factor (ratio) is that, and how would you apply the correct power law to speed? • Once you find the new speed from your calculation, which of the options is closest to your result?
• Compute the fuel ratio: new consumption ÷ old consumption • Apply the correct exponent (often 1/3 if fuel ~ speed³) to the fuel ratio to get the speed ratio • Multiply the original speed by the speed ratio and compare with all four answer choices
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