While steaming at 17.0 knots, your vessel consumes 382 barrels of fuel oil per day. In order to reduce consumption to 223 barrels of fuel oil per day, what is the maximum speed the vessel can turn for?
• Relationship between speed and fuel consumption for displacement vessels (fuel roughly proportional to the cube of speed) • How to set up a ratio/proportion when one quantity changes with the cube of another • Converting barrels per day and knots into a comparative formula without changing units
• How can you relate the initial and final fuel consumptions using only the ratio of the speeds, without converting any units? • If fuel consumption is proportional to the cube of speed, what equation can you write that involves the two speeds and the two fuel consumptions? • After finding the new speed from your equation, which of the multiple-choice options most closely matches your calculated value?
• Confirm you are using a cube relationship (speed³) between fuel consumption and speed, not a square or linear one • Check that your ratios keep initial values together and new values together (don’t mix them up in the fraction) • Verify your final speed is less than 17.0 knots and that it makes sense given the reduction in fuel consumption
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