While steaming at 16.3 knots, your vessel consumes 363 barrels of fuel oil per day. In order to reduce consumption to 298 barrels of fuel oil per day, what is the maximum speed the vessel can turn for?
• Fuel consumption vs. speed relationship (typically proportional to the cube of the speed for displacement vessels in many exam problems) • Using ratios instead of recalculating from scratch: ( (V_2 / V_1)^3 = (C_2 / C_1) ) if cube law applies • Careful unit consistency: both consumptions are in barrels per day and speeds in knots
• How does a reduction in fuel consumption (from 363 to 298 barrels/day) affect speed if consumption is proportional to the cube of speed? Should the new speed be higher or lower than 16.3 knots? • Can you set up a proportion using the cube law, like ( (V_2 / 16.3)^3 = 298 / 363 ), and then solve step by step for ( V_2 )? • After you compute the new speed, which answer choice is closest to your calculated value?
• Confirm you’re assuming fuel consumption ∝ speed³ (a common exam assumption unless told otherwise). • Double-check the ratio direction: put new consumption over old consumption on the same side as new speed over old speed. • Verify your final speed is less than 16.3 knots but still reasonable compared to the percentage drop in consumption.
No comments yet
Be the first to share your thoughts!