While steaming at 15.5 knots, your vessel consumes 333 barrels of fuel oil per day. In order to reduce consumption to 176 barrels of fuel oil per day, what is the maximum speed the vessel can turn for?
• Relationship between speed and fuel consumption for displacement vessels (fuel roughly proportional to the cube of speed) • Setting up a ratio or proportion between the two conditions (known speed/consumption vs. unknown speed/new consumption) • Careful handling of exponents (power of 3) when solving for the new speed
• How does fuel consumption change when speed changes on a displacement ship? Is it linear, squared, or cubed? • If 333 barrels/day corresponds to 15.5 knots, how can you express this as an equation that links consumption to speed? • Once you write the proportion using the correct power of speed, how do you isolate the new speed term to solve for it?
• Confirm you’re using the same time unit (per day) for both consumption values • Make sure you raise the speed ratio to the correct power that reflects fuel–speed relationship • Use your calculator carefully to compute the final speed and then compare your result to the closest answer choice
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