While preparing for a storm when elevated, the total weight of the COASTAL DRILLER is 14,150 kips, LM are 1,712,150 ft-kips, and TM are -9,905 ft-kips. The bow leg reaction is __________.
• Use static equilibrium: sum of vertical reactions must equal the total weight • Relate longitudinal moment (LM) to the difference in reactions between fore and aft legs • Understand how sign convention (positive/negative moments) affects which leg carries more load
• First, assume three legs and think about how the total vertical reaction is shared among them in calm, symmetric conditions versus during a storm prep condition • Ask yourself: how does a non‑zero LM shift load toward the bow or stern leg? Which direction does a positive LM push the load, under the given sign convention? • Once you find the individual leg reactions using the LM, compare which one corresponds to the bow leg, then match it to the closest choice
• Confirm that the sum of all leg reactions = 14,150 kips (total weight) • Check that the moments created by your leg reactions about the chosen reference point match the given LM (1,712,150 ft‑kips) within rounding • Verify that the sign of LM you used is consistent with the problem’s convention so you don’t accidentally swap bow and stern leg reactions
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