While preparing for a storm when elevated,...

Question 1 of 2707066636ee728f7522a1c518642

While preparing for a storm when elevated, the total weight of the COASTAL DRILLER is 14,150 kips, LM are 1,712,150 ft-kips, and TM are -9,905 ft-kips. The starboard leg reaction is __________.

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Question 1 of 27070

While preparing for a storm when elevated, the total weight of the COASTAL DRILLER is 14,150 kips, LM are 1,712,150 ft-kips, and TM are -9,905 ft-kips. The starboard leg reaction is __________.

🔍 Key Concepts

• How to compute individual leg reactions from total displacement (total weight) and trim moments on a three-legged jack-up rig • Relationship between transverse moment (TM) and the difference between port and starboard leg reactions • Effect (or lack of effect) of longitudinal moment (LM) on the side-to-side (port vs. starboard) load distribution

💭 Think About

• First, if there were no trim moments, what would be the equal reaction on each of the three legs from the total weight? • Then, ask: does the longitudinal moment (LM) change the difference between port and starboard leg reactions, or does that come only from the transverse moment (TM)? • How does the sign of the transverse moment (TM) tell you which side (port or starboard) is taking more load, and by how much when divided between the legs on that side?

✅ Before You Answer

• Be sure you convert moment = force × distance correctly when relating TM to the leg reactions • Confirm how many legs share the port-side reaction and how many share the starboard-side reaction, and whether they are assumed symmetric • After adjusting for TM, verify that the sum of all leg reactions still equals the total weight of 14,150 kips