When an emergency transmitter uses 325 watts and a receiver uses 50 watts, how many hours can a 12.6 volt, 55 ampere-hour battery supply full power to both units?
• Power, current, and voltage relationship: ( P = V \times I ) and how to solve for current when power and voltage are known • Ampere-hours (Ah) and how they relate to current and time: ( ,\text{Ah} = I \times t ,) • Adding the total power of multiple devices to find the combined load on the battery
• How can you find the total power used by the transmitter and receiver together before doing anything else? • Once you know the total power and the battery voltage, how can you calculate the total current draw from the battery? Which formula links power, voltage, and current? • After finding the current draw, how does the battery’s ampere-hour rating tell you how long it can supply that current?
• Be sure you add the two power values (325 W and 50 W) to find the total power first • Use the correct formula: ( I = \frac{P}{V} ) with total power and battery voltage to get current in amperes • Check that you use the battery rating 55 ampere-hours with ( t = \frac{\text{Ah}}{I} ) to find time in hours, not minutes or seconds
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