When an emergency transmitter uses 325 watts...

Question 1 of 27070uNBV5ue9z7cYMErbra3o

When an emergency transmitter uses 325 watts and a receiver uses 50 watts, how many hours can a 12.6 volt, 55 ampere-hour battery supply full power to both units?

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Question 1 of 27070

When an emergency transmitter uses 325 watts and a receiver uses 50 watts, how many hours can a 12.6 volt, 55 ampere-hour battery supply full power to both units?

🔍 Key Concepts

• Power, current, and voltage relationship: $P = V \times I$ and how to solve for current when power and voltage are known • Ampere-hours (Ah) and how they relate to current and time: $\,\text{Ah} = I \times t \,$ • Adding the total power of multiple devices to find the combined load on the battery

💭 Think About

• How can you find the total power used by the transmitter and receiver together before doing anything else? • Once you know the total power and the battery voltage, how can you calculate the total current draw from the battery? Which formula links power, voltage, and current? • After finding the current draw, how does the battery’s ampere-hour rating tell you how long it can supply that current?

✅ Before You Answer

• Be sure you add the two power values (325 W and 50 W) to find the total power first • Use the correct formula: $I = \frac{P}{V}$ with total power and battery voltage to get current in amperes • Check that you use the battery rating 55 ampere-hours with $t = \frac{\text{Ah}}{I}$ to find time in hours, not minutes or seconds