What is the transverse shift in the center of gravity if 200 short tons are placed 10 feet to port of the centerline on a MODU with TCG 0.7 foot starboard of the centerline, and the displacement is 9,000 short tons?
• Transverse shift of center of gravity uses the moment formula: GG' = (w × d) / Δ • Be careful with direction: port vs starboard and initial TCG position • Combine the initial TCG with the calculated shift to get the final TCG from centerline
• First, ignore the initial TCG and compute how far G will move due to putting 200 tons 10 ft off centerline on a 9,000‑ton vessel. Which formula connects weight, distance, displacement, and shift? • Decide whether this movement is toward port or starboard, then apply it to the original 0.7 ft starboard position. Will the new G end up to port or still to starboard? • Once you know the final TCG from centerline, compare its distance from centerline with the answer choices. Which value is closest to your computed shift FROM the original position?
• Use the formula GG' = (w × d) / Δ with consistent units (all in short tons and feet) • Confirm whether the question is asking for the amount of shift (GG') or the final TCG position from centerline • Double‑check the sign/direction: port shift should reduce a starboard TCG and may cross to the other side of the centerline
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