🔍 Key Concepts

• Peak inverse voltage (PIV) of rectifier tubes in a center-tapped full-wave circuit • Relationship between secondary voltage per half-winding and total secondary voltage in a center-tapped transformer • How the peak value of an AC sine wave relates to its RMS value (√2 factor)

💭 Think About

• In a center-tapped full-wave rectifier, how much reverse voltage does each tube actually see in terms of the transformer's secondary voltage? Draw the waveform if it helps. • How does the total secondary RMS voltage relate to the RMS voltage of each half of the winding, and then to the peak voltage of that half? • Given the tube’s PIV rating, set up an inequality that keeps the maximum reverse voltage on any tube less than or equal to 10,000 V and solve for the allowable transformer secondary voltage.

✅ Before You Answer

• Be clear whether the 10,000 V PIV applies to the reverse voltage across one tube, not the total transformer secondary. • Remember that each half of the secondary has its own RMS voltage, and its peak voltage = RMS × √2. • Double-check whether the voltage that appears across the non-conducting tube includes the voltage from both halves of the secondary relative to the center tap.