What is the change in the vertical moments (excluding free surface effects) for the COASTAL DRILLER if 2.0 feet of drill water is transferred from a full drill water tank 23 to an empty drill water tank 6?
• Vertical moment change when weight is moved: ( \Delta M = W (z_{final} - z_{initial}) ) • How to find the weight of 2.0 feet of water from the tank calibration or capacity tables • Sign convention: moving weight up vs down relative to the baseline and how that affects the sign of the vertical moment
• First, think about whether the receiving tank’s center of gravity is higher or lower than the sending tank’s center of gravity relative to the baseline. Are you moving the weight up or down? • From the tank tables, how do you get the weight of just 2.0 feet of water in each tank, not the full tank weight? • Once you know the vertical positions (z) of each tank’s center and the amount of weight moved, how would you combine those to get a single net change in vertical moments?
• Be clear on the direction of movement (from which tank to which tank) and which tank is higher above the baseline. • Confirm the correct weight of water moved using tank calibration data for 2.0 feet, not the full tank capacity. • Check the sign of the result: does your computed change in vertical moment represent moving weight up (increasing) or down (decreasing), and which answer choices match that sign and magnitude?
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