What is the approximate geographic visibility of an object with a height above the water of 70 feet, for an observer with a height of eye of 65 feet?
⢠Geographic range of visibility (based on curvature of the Earth, not light intensity) ⢠Formula for distance to the horizon in nautical miles using height of eye or object height in feet ⢠Adding the observerâs horizon distance and the objectâs horizon distance to find total range
⢠How do you convert a height in feet to distance to the horizon in nautical miles? Write the formula and compute it for both 70 ft and 65 ft. ⢠Once you know how far the observer can see to their own horizon and how far the objectâs top is above its own horizon, how do you combine those two distances? ⢠After doing both calculations and combining them, which choice is numerically closest to your result?
⢠Make sure you use the correct constant in the horizon distance formula (commonly about 1.17 Ă âheight in feet when distance is in nautical miles). ⢠Calculate horizon distance separately for the 70âft object and the 65âft height of eye before adding. ⢠Check that your final value is reasonable (over 10 nm but under 25 nm) before matching to the nearest answer choice.
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