The illustrated shaft has an overall length of 42 inches. If the diameter of "E" = 2.50" and "F" = 3.750", with an indicated radius of "R" = .125" and the taper per foot, "L" = 1.5"; then the tapered length "X" is __________. See illustration GS-0133.
ā¢ Taper per foot (L) describes how much the DIAMETER changes over 12 inches of length, not the radius ā¢ You are given starting and ending diameters (E and F) of the taper ā relate their difference to the taper-per-foot value ā¢ Remember the indicated radius R = 0.125 in is a small fillet at each end; think carefully about whether it should change the basic taper length calculation
ā¢ How much does the diameter change between E and F, and how does that compare to the meaning of 1.5 inches taper per foot? ā¢ Once you know how many inches of length are needed for that change in diameter, how could the fillet radii at each end slightly increase the drawn length X? ā¢ Which of the answer choices is closest to the theoretical taper length you compute from the diameters and taper-per-foot alone?
ā¢ Compute the diameter difference (F ā E) correctly in inches ā¢ Convert taper per foot into taper per inch before solving for length ā¢ Decide explicitly whether R at each end adds to X (and by how much) based on how the taper is drawn in the illustration
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