The DEEP DRILLER, loaded as shown in the Sample Load Form #4 (Drilling), discharges a non-liquid load of 275.8 long tons from a position 130 feet above the keel, 40 feet forward of amidships, and 30 feet to port of the centerline. What is the resulting list angle?
• Effect of removing a weight on transverse stability and list (consider it as adding an equal weight in the opposite direction) • How to calculate transverse moment from a weight times its vertical and transverse distances from the centerline • Using the metacentric height (GM) from the Sample Load Form to find the angle of list: ( , \tan\theta = \frac{w \times d}{\Delta \times GM} ,)
• When a weight is discharged, in which direction does the vessel tend to heel relative to the original weight’s position (port or starboard)? • How does the horizontal distance from the centerline (30 ft) of the removed weight affect the heeling moment, and how is that related to the total displacement from the Sample Load Form? • Once you compute ( \tan\theta ), how do you convert it to degrees, and how does the sign tell you whether the list is to port or starboard?
• Confirm the vessel’s displacement (Δ) and GM (transverse metacentric height) from Sample Load Form #4 before doing any calculation • Be sure you treat removing 275.8 LT as creating a heeling moment in the opposite direction of where the weight was located • After finding (\theta), check if the direction of list (port or starboard) matches your sign convention before choosing from the options
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