The DEEP DRILLER, loaded as shown in the...

Question 1 of 2707066636ee728f7522a1c5178de

The DEEP DRILLER, loaded as shown in the Sample Load Form #4 (Drilling), discharges a non-liquid load of 275.8 long tons from a position 130 feet above the centerline. What is the improvement in KGT?

Back

Question 1 of 27070

The DEEP DRILLER, loaded as shown in the Sample Load Form #4 (Drilling), discharges a non-liquid load of 275.8 long tons from a position 130 feet above the centerline. What is the improvement in KGT?

🔍 Key Concepts

• KG and KGT changes when weights are added, removed, or shifted • Using the moment of a weight about the keel (W × KG) to find the change in KG • Difference between lightship / displacement and the weight being discharged

💭 Think About

• What happens to the ship’s vertical center of gravity when you REMOVE a weight located high above the keel? Think about whether KG goes up or down and why. • How do you calculate the change in KG using the weight removed, its KG, and the ship’s total displacement from Sample Load Form #4? • Once you find the change in KG, how do you apply it to find the NEW KGT and then the improvement in KGT compared with the original value?

✅ Before You Answer

• From Sample Load Form #4, identify the total displacement and the initial KGT before discharging the weight. • Compute the moment of the weight being discharged: W × KG (use 130 ft for KG here), and use the correct sign for a weight removed. • Use the correct formula for change of KG with weight removed: ΔKG = (w × (KG_removed − KG_original)) ÷ (displacement − w), and then compare old and new KGT to see the improvement.