The DEEP DRILLER is loaded as shown in the...

Question 1 of 2707066636ee728f7522a1c5178d7

The DEEP DRILLER is loaded as shown in the sample Load Form #3 (Preparing to Drill). If the liquid mud in mud pit #4 (see table 8) is dumped, what would be the new uncorrected height of the center of gravity?

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Question 1 of 27070

🔍 Key Concepts

• Center of gravity (KG) calculation from a load form (using total weight and total moments). • Effect of removing a weight high or low on the vessel’s overall KG. • How to use the data for mud pit #4 (weight and vertical height) in the sample Load Form #3 / Table 8.

💭 Think About

• On your current load form, how is the uncorrected KG obtained from the total vertical moment and total displacement? Think about the basic formula. • If mud pit #4 is dumped, what exactly changes on the form: the total displacement, the total vertical moment, or both? How do you adjust them? • Is mud pit #4 located relatively high or low compared with the current KG? Based on that, should the new KG move up or down, and by about how much? Does that help you rule out any choices?

✅ Before You Answer

• Re‑calculate the new total displacement after removing the contents of mud pit #4 (subtract that weight only). • Re‑calculate the new total vertical moment by subtracting the moment of mud pit #4 (its weight × its vertical distance above baseline). • Use the KG formula KG = Total vertical moment ÷ Total displacement with your new totals, and then compare the result carefully with the answer choices (watch your units and rounding).