The DEEP DRILLER, at a draft of 19 feet, has a KGL of 59.91 feet and an LCG of 1.57 feet. What is the trim angle?
• Longitudinal Center of Gravity (LCG) and how its position relative to midships affects trim • Relationship between LCG, longitudinal metacentric height (GMₗ), and trim angle (in radians or degrees) • How small-angle approximations (tan θ ≈ θ in radians) are used in trim calculations
• How does a small forward or aft shift of the LCG change the trimming moment of the vessel? Is a positive LCG value measured forward or aft of midships in your reference system? • Once you relate LCG to trimming moment and to GMₗ, how can you express the trim angle θ using a right triangle or small-angle formula? • After finding θ in radians, how do you correctly convert it to degrees and match it to the closest multiple of 0.1° in the answer choices?
• Be clear on the sign convention for LCG (is positive forward or aft?) and how that decides whether the vessel trims by the bow or by the stern. • Make sure you are using the correct longitudinal GM (GMₗ), not the transverse GM, in the trim-angle formula. • After calculating θ, convert radians to degrees carefully and then compare with the options (0.2°, 0.3°, 0.4°, 0.5°) to see which one is the closest.
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