The DEEP DRILLER, at 60.0 feet draft in sea water, has VM = 974,441 foot-long tons, LM = 3 foot-long tons, FSML = 30,572 foot-long tons, and FSMT = 18,732 foot-long tons. What is the transverse free surface correction to KG?
• Free surface effect (FSE) and how it affects KG (height of center of gravity) • Relationship between FSMT (transverse free surface moment), displacement, and correction to KG • Difference between longitudinal and transverse free surface corrections
• Which of the given moments (VM, LM, FSML, FSMT) relate specifically to transverse stability and therefore to the correction in the transverse KG? • How do you convert a moment (in foot-long tons) into a height correction (in feet) using the vessel’s displacement or virtual mass? • Is there any reason in this condition that the transverse free surface correction might be zero, or should it be a positive number added to KG?
• Confirm which quantity represents the vessel’s displacement/virtual mass that must be used in the denominator for a KG correction. • Use the correct unit relationship: a moment (ft‑LT) divided by a weight (LT) gives a distance in feet. • Make sure you are using FSMT only for transverse KG correction and not the longitudinal values.
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