The COASTAL DRILLER, while drilling, has a total weight of 15,400 kips. The LCG is 120.00 feet AF0, and the TCG is -0.5 feet to port of the centerline. What is the bow leg reaction?
• Longitudinal center of gravity (LCG) and how it distributes weight between fore and aft supports • The idea that the sum of leg reactions must equal total weight • Using moments about a reference point (forward or aft) to solve for unknown reactions
• How can you treat the three legs of the COASTAL DRILLER like supports in a statics problem, similar to a beam with multiple supports? • If you know the total weight and the LCG from a reference (AF0), how do you use moments to find how much load is carried at the bow versus at the stern legs? • Once you find the total bow reaction, how would port–starboard (TCG) effects influence distribution between the individual bow legs, if at all, for this specific question?
• Confirm that all vertical reactions add up exactly to 15,400 kips • Carefully set up the moment equation about a chosen reference point using the LCG = 120 ft AF0 • Verify whether the TCG value (-0.5 ft) actually affects the total bow leg reaction or only the split between port and starboard at the bow
No comments yet
Be the first to share your thoughts!