The COASTAL DRILLER is drilling while weighing 15,436 kips. LM are 2,006,680 ft-kips, and TM are -7,718 ft-kips. What is the port leg reaction?
• Static equilibrium of forces and moments on a three‑leg jack‑up or similar structure • Relationship between total weight and the sum of leg reactions • Using longitudinal (LM) and transverse (TM) moments to split total reaction into individual leg loads
• First, think about how the total vertical reaction from all legs relates to the vessel’s total weight. What must those add up to? • Then consider how the given longitudinal and transverse moments (LM and TM) help you determine how that total reaction is distributed between port and starboard legs. • Try to write simultaneous equations for the unknown leg reactions using: (1) sum of vertical forces, (2) sum of moments about one axis, and (3) sum of moments about the other axis.
• Confirm that the sum of all leg reactions equals 15,436 kips (total weight). • Double‑check your sign convention for LM and TM when setting up the moment equations so that port vs. starboard reactions are treated consistently. • After solving, verify that your computed leg reactions, when plugged back into both moment equations (LM and TM), reproduce the given LM = 2,006,680 ft‑kips and TM = -7,718 ft‑kips.
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