The barge shown in the illustration is 40' X 20' X 10' (12.192 m X 6.096 m X 3.048 m) and weighs 22.9 long tons when empty. It has been loaded to a draft of 8 feet in salt water. How many long tons of cargo have been added? See illustration GS-0157.
⢠Use Archimedesā principle: the weight of water displaced equals the vesselās total weight at that draft. ⢠Compute the underwater volume using the bargeās length, width, and draft shown in the illustration (assume box-shaped underwater body). ⢠Convert displaced volume of salt water to long tons using the proper weight of 1 cubic foot of salt water.
⢠What is the underwater volume of the barge at an 8āfoot draft, based on the dimensions in the figure? ⢠Given the weight of 1 cubic foot of salt water, how many long tons does that underwater volume represent? ⢠Once you know the total displacement at 8 feet, how do you use the bargeās light weight (empty weight) to find just the cargo weight?
⢠Be sure you are using the correct density for salt water (in pounds per cubic foot), not fresh water. ⢠Convert from pounds to long tons (2240 lb per long ton) before comparing with the choices. ⢠After finding total displacement, subtract the light ship weight (22.9 LT) to isolate the cargo weight only.
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