The barge shown in the illustration is 40' X...

Question 1 / 205eccef9dbacbc34ba4d45e0f

Question 1 of 205eccef9dbacbc34ba4d45e0f

The barge shown in the illustration is 40' X 20' X 10' (12.192 m X 6.096 m X 3.048 m ) and weighs 22.9 long tons (23.28 t) when empty. It has been loaded to a draft of 5 feet (1.524 m) in salt water. How many long tons of cargo have been added? See illustration GS-0157.

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🔍 Key Concepts

• Use Archimedes’ principle: the barge’s total weight when loaded equals the weight of the water displaced at 5 ft draft • Compute displacement in salt water using: Volume (ft³) × 64 lb/ft³, then convert pounds to long tons (2240 lb) • Remember to subtract the lightship weight (22.9 long tons) from the total loaded displacement to get cargo weight

💭 Think About

• Based on the 40’ × 20’ dimensions and a 5 ft draft, what is the underwater volume of the barge if you treat it as a simple rectangular box, as suggested by the illustration? • Once you find the total displacement in long tons at 5 ft draft, how does that compare to the barge’s empty weight, and what does the difference represent? • Which of the choices is closest to the cargo weight you get after converting from pounds to long tons and rounding reasonably?

✅ Before You Answer

• Carefully multiply L × W × draft in feet to get the underwater volume in cubic feet • Use 64 lb/ft³ for salt water density and 2240 lb/long ton in your conversions • Be sure to subtract the 22.9 long tons lightship weight at the end, not at the beginning

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Question 1 of 20

19.4 long tons (19.72 t)

49.1 long tons (49.91 t)

91.4 long tons (92.91 t)

94.1 long tons (95.65 t)

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Question 1 / 205eccef9dbacbc34ba4d45e0f

Question 1 of 205eccef9dbacbc34ba4d45e0f

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Question 1 of 20

5eccef9dbacbc34ba4d45e0f

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🔍 Key Concepts

💭 Think About

✅ Before You Answer

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

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