The ball float shown in the illustration is 9 inches in diameter and is floats in a liquid with a specific gravity of 0.9. If the effective length (EL) is 18 inches and "L" is 3 inches, how many pounds of force will be available at "X" if there is no mechanical loss? See illustration GS-0158.
• Buoyancy force from a float ball as shown on the GS-0158 chart (ball diameter vs. specific gravity vs. available operating force) • Moments (torque) about a pivot: force × distance must balance on both sides of the lever • Lever arm ratio between the effective float arm (EL) and the short arm to point L/X
• From the chart, for a 9-inch ball in a liquid of specific gravity 0.9, what is the available operating force at the ball (in pounds)? • Once you know the force at the ball, how does multiplying that force by EL (18 inches) give you the torque about the pivot? • If the same torque acts through the short 3-inch arm to point X, what force at X will produce that same torque?
• Be sure you are using the correct curve for 9-inch ball diameter on the chart and the correct specific gravity value (0.9) on the vertical axis. • Confirm that you compute torque as Force × Distance (inches) on BOTH sides of the pivot and then set them equal. • Check that your final force at X is scaled by the ratio of the arm lengths (EL : L) and that your answer matches one of the choices.
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