Ten triangular piles of piping on the pier...

Question 1 / 2066636ee728f7522a1c518bf5

Question 1 of 2066636ee728f7522a1c518bf5

Ten triangular piles of piping on the pier are to be loaded - each pile has a 20 foot base, is 15 feet high and 30 feet long. If the breadth of the hold is 60 feet and the piping is to be stowed fore and aft in a 30 foot space, how high will it stow?

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🔍 Key Concepts

• Volume of a triangular prism-shaped pile (think: triangle base × length) • Total available deck/hold footprint for stowage (breadth × length of space) • How stacking affects height when total volume is conserved but base area changes

💭 Think About

• First, compute the volume of ONE triangular pile from the given base, height, and length. Then multiply by the total number of piles to get total volume to be stowed. • Figure out the floor area in the hold where these piles will be stowed, using the given breadth and length of the stowage space. • If you keep the same total volume but change the footprint area, what must happen to the height? Use the relationship: Volume = area of base × height of stowage layer.

✅ Before You Answer

• Be sure you are using the correct formula for the area of a triangle (not a rectangle) when finding the cross-section of one pile. • Confirm the units are consistent (all in feet) before calculating volume and final height. • After you compute the stowage height, compare it to the choices and check whether the result is reasonable relative to the original 15 ft pile height.

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Question 1 of 20

16.6 feet

25.0 feet

50.0 feet

75.0 feet

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Question 1 / 2066636ee728f7522a1c518bf5

Question 1 of 2066636ee728f7522a1c518bf5

Back

Question 1 of 20

66636ee728f7522a1c518bf5

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🔍 Key Concepts

💭 Think About

✅ Before You Answer

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