On a vessel of 12,000 tons displacement, a tank 60 feet long, 50 feet wide, and 20 feet deep is half filled with fresh water (SG 1.000) while the vessel is floating in saltwater (SG 1.026) What is the reduction in metacentric height due to free surface?
• Free surface effect (FSE) formula for reduction in GM: ( , , \text{Free Surface Correction} = \frac{\rho_{liquid}}{\rho_{sea}} \cdot \frac{I}{\Delta} , , ) where (I) is second moment of area of the free surface and (\Delta) is displacement • How to compute second moment of area for a rectangular tank free surface: ( I = \frac{b^3 l}{12} ) (be clear which dimension is which) • Effect of different specific gravities (SG) inside the tank and outside the ship on the free surface correction
• Which tank dimensions represent the free surface plane (the surface of the water) and which dimension should not be used in the moment of inertia calculation? • How do you convert the given displacement in tons into consistent units that match the tank dimensions given in feet? • How does the fact that the tank liquid is fresh water while the vessel floats in saltwater change the basic free surface correction? Do you need to apply a density (SG) ratio?
• Be sure you are using the correct formula for the second moment of area of a rectangle about a horizontal axis through its centroid, matching the free surface plane dimensions. • Verify that all units are consistent: length in feet, displacement in long tons vs. weight in pounds, and that (g) cancels appropriately if you use weight instead of mass. • Before picking an answer, confirm whether you have applied the SG ratio (fresh vs. salt) correctly in the free surface correction; a missing or inverted ratio will push your result noticeably away from the correct choice.
No comments yet
Be the first to share your thoughts!