On 20 November your 1030 ZT DR position is...

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Question 1 of 2066636eea28f7522a1c51ac44

On 20 November your 1030 ZT DR position is LAT 27°16.0'N, LONG 157°18.6'E. You are on course 060°T at a speed of 20 knots. You observed 3 celestial bodies. Determine the latitude and longitude of your 1200 running fix.

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Question 1 of 20

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🔍 Key Concepts

• Dead reckoning (DR) position and how course and speed advance your position over time • Converting speed in knots and time in hours to distance run along a track line • How a running fix relates to your DR track between 1030 and 1200

💭 Think About

• From 1030 ZT to 1200 ZT, how many hours pass, and how far do you travel at 20 knots in that time? • Along a true course of 060°, in which direction (NE, SE, etc.) do latitude and longitude change, and which should change more for this short run? • Compare how much each answer choice’s latitude and longitude differ from the 1030 DR position: which set of changes most closely matches a 20‑knot run on 060° for that time interval?

✅ Before You Answer

• Compute the run in nautical miles using Speed = Distance / Time, and be sure time is in hours and fractions of an hour • Check that the change in latitude and change in longitude from 1030 to 1200 are reasonable for the course 060°T (northeasterly) • Verify that only one choice has both a plausible northeasterly shift and a total distance from the DR that is close to your computed run

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