If the manufacturer advises of a normal lube oil consumption for a 4000 horsepower (2982.8 kW) diesel engine to be .0001 gal/hp-hr, (.5076 mL/kW-hr), how much oil should the engine consume in one 24 hour period if operated at full load?
• Using the lube oil consumption rate .0001 gal/hp-hr as a conversion factor • Relating horsepower, time in hours, and consumption rate to get total gallons • Checking consistency of units (hp, hr, gal) throughout the calculation
• What single formula can you write that includes horsepower, hours of operation, and consumption per hp-hr all multiplied together? • How many horsepower-hours (hp-hr) does a 4000 hp engine produce in 24 hours at full load? Once you have hp-hr, how do you convert that to gallons using the given rate? • After you calculate the total gallons, which choice is closest to your computed value?
• Be sure you multiply by 24 hours, not by 1 hour or by 4000 twice. • Confirm that your final answer is in gallons, not hp-hr or some other unit. • Double-check that you are using .0001 gal per hp-hr, not .001 or .01; a misplaced decimal will change the answer by a factor of 10.
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