If a particular liquid has a specific...

Question 1 of 270705eccefa2bacbc34ba4d479d5

If a particular liquid has a specific gravity of 0.96 kg/dm3 at 77°F, what will be the specific gravity of the liquid, as determined from the graph shown in the illustration, if the temperature is increased to 167°F? Illustration MO-0113

Back

Question 1 of 27070

No Illustration

This question does not have an illustration

🔍 Key Concepts

• Use the left vertical axis (kg/dm³) to find 0.96 at the initial temperature of 77°F (25°C). • Follow the oil density curve (solid blue line, not the dashed water line) horizontally to the right until you reach the new temperature of 167°F (~75°C). • Notice that the density (specific gravity) decreases with increasing temperature, so the final value must be less than 0.96 kg/dm³ but still on the same oil curve.

💭 Think About

• First, locate the starting point: where does 0.96 kg/dm³ at 77°F fall on the oil curve in the graph? • From that exact point on the curve, if you move horizontally to the right until you reach 167°F, what density value does the curve intersect on the vertical axis grid? • Comparing that intersection to the answer choices, which option is closest to the curve’s value at 167°F?

✅ Before You Answer

• Confirm you are using the solid oil curve that passes through 0.96 kg/dm³ at 77°F, not a neighboring curve. • Verify that you read temperature along the top axis in °F, and that 167°F is correctly located between 160°F and 170°F grid lines. • Double‑check the vertical reading at the new intersection, making sure it is slightly below 0.92 kg/dm³ to match the trend shown by the curve.