An elevated jack-up weighs 14,000 kips. The drill floor, weighing 700 kips, is skidded 10.0 feet to starboard. The change in TCG is __________.
β’ Transverse shift of center of gravity (TCG) due to moving a weight sideways β’ Using the moment = weight Γ distance concept for calculating shift of G β’ Total displacement vs. weight being moved and how they relate in the formula
β’ How does moving a smaller weight on a larger structure affect the combined center of gravity? Will it move more, less, or the same as the distance skidded? β’ What formula links the moved weight, the distance it is moved, and the resulting change in TCG of the whole jack-up? β’ After you compute the change in TCG, should it be a large shift (many feet) or a relatively small shift given the total weight?
β’ Write and use the standard shift of G formula for transverse movement: change in TCG = (w Γ d) / W β’ Make sure units are consistent (all in kips and feet) before plugging into the formula β’ Confirm the direction of the shift (port or starboard) based on which way the drill floor is moved
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