An elevated jack-up weighs 14,000 kips. Its...

Question 1 of 2707066636ee728f7522a1c517a6b

An elevated jack-up weighs 14,000 kips. Its TCG is located 1.0 foot to starboard of the centerline. What would be the new TCG for the jack-up if the drill floor, weighing 700 kips, is skidded 10 feet to port?

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Question 1 of 27070

🔍 Key Concepts

• Transverse Center of Gravity (TCG) moves toward added weight and away from removed weight • Use the moment = weight × distance concept to find total transverse moments before and after the move • The new TCG = (sum of transverse moments) ÷ (total weight)

💭 Think About

• What is the total transverse moment of the jack-up before the drill floor is moved, using its given TCG and total weight? • When the drill floor is skidded 10 feet to port, what is the change in its transverse moment (include the sign: port vs. starboard)? • After you add the new drill floor moment to the original jack-up moment, what do you get for the combined moment and how does that compare with the total weight to find the new TCG?

✅ Before You Answer

• Keep a clear sign convention: choose port as (-) and starboard as (+), or the reverse, and stay consistent • Be sure you use total weight (original jack-up + drill floor) for the new TCG calculation • Double-check that your final TCG direction (port/starboard) matches the sign you obtain from the calculation