A three inch overboard discharge line,...

Question 1 / 205eccef9bbacbc34ba4d4551a

Question 1 of 205eccef9bbacbc34ba4d4551a

A three inch overboard discharge line, located six feet below the waterline, has ruptured and separated from the hull. What would be the minimum number of strokes per minute required from a 8" x 12" x 12" duplex double acting reciprocating bilge pump, operating at 82% efficiency, to keep the bilge level from continuing to rise? See illustration SF-0034.

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🔍 Key Concepts

• Use the SF-0034 table to find the gallons per minute (gpm) entering through a 3-inch hole at 6 feet of head. • Compute the theoretical displacement per stroke of one side of the pump from its dimensions (8" x 12"), then account for duplex double-acting operation. • Apply the pump efficiency (82%) to get actual gpm, then relate gpm = gallons per stroke × strokes per minute.

💭 Think About

• How many gallons per minute are flooding in through the ruptured line according to the table, and why is that the minimum you must pump out? • Given the cylinder dimensions, how many cubic inches (and then gallons) are moved per stroke on one side, and how does duplex double-acting change that volume per stroke of the pump? • Once you know gallons per stroke and gallons per minute flooding in, what strokes per minute will just balance the inflow after considering 82% efficiency?

✅ Before You Answer

• Be sure you selected the correct row (3 in) and column (6 ft) from SF-0034. • Convert cubic inches to gallons using the correct factor: 1 gallon ≈ 231 in³. • Confirm you multiplied by both cylinders and both directions of stroke for a duplex double-acting pump before applying 82% efficiency.

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Question 1 of 20

45 strokes per minute

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Question 1 / 205eccef9bbacbc34ba4d4551a

Question 1 of 205eccef9bbacbc34ba4d4551a

Back

Question 1 of 20

5eccef9bbacbc34ba4d4551a

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🔍 Key Concepts

💭 Think About

✅ Before You Answer

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