A semisubmersible, with a TCG of 0.5 foot to...

A semisubmersible, with a TCG of 0.5 foot to...

Question 1 of 2707066636ee728f7522a1c51889e

A semisubmersible, with a TCG of 0.5 foot to port, displaces 20,000 long tons. Bulk, weighing 400 long tons, is loaded in P-tanks located 50 feet starboard to the centerline. What is the new TCG?

Question 1 of 27070

Q

A semisubmersible, with a TCG of 0.5 foot to port, displaces 20,000 long tons. Bulk, weighing 400 long tons, is loaded in P-tanks located 50 feet starboard to the centerline. What is the new TCG?

🔍 Key Concepts

• Transverse Center of Gravity (TCG) and how adding weight off the centerline creates a moment • Using moments: Weight × Distance = Moment (with port and starboard treated as opposite signs) • The formula for a new TCG after adding weight: combine old moment and added moment, then divide by new total displacement

💭 Think About

• First, convert the original TCG (0.5 ft to port) into a transverse moment using the vessel’s original displacement. Which direction (sign) should you assign to port vs. starboard? • Next, calculate the moment created by the 400 LT loaded 50 ft to starboard. How does this compare in size and direction to the original moment? • After you find the net transverse moment, divide it by the new total displacement to find the new TCG. Is the final TCG to port or to starboard, and should it be slightly more, equal, or much more than 0.5 ft away from centerline?

✅ Before You Answer

• Be sure you treat port and starboard as opposite signs when adding moments (e.g., port negative, starboard positive, or vice versa, but be consistent). • Confirm you used the new total displacement (original + added weight) when computing the final TCG. • Check if your final answer’s direction (port or starboard) and magnitude make sense: you started with a small offset to port and added a relatively large weight far to starboard.