A semisubmersible, with a TCG of 0.5 feet to...

A semisubmersible, with a TCG of 0.5 feet to...

Question 1 of 2707066636ee728f7522a1c51889d

A semisubmersible, with a TCG of 0.5 feet to port, displaces 20,000 long tons. Bulk, weighing 400 long tons, is discharged from P-tanks located 50 feet starboard of the centerline. What is the new TCG?

Question 1 of 27070

Q

A semisubmersible, with a TCG of 0.5 feet to port, displaces 20,000 long tons. Bulk, weighing 400 long tons, is discharged from P-tanks located 50 feet starboard of the centerline. What is the new TCG?

🔍 Key Concepts

• Transverse center of gravity (TCG) and how port/starboard positions are treated as positive or negative values • Effect on TCG when a weight is removed off-center (compare formulas for shifting G when weight is added vs when weight is removed) • Using the relation: GG' = (w × d) / (new displacement) and then combining with the original TCG

💭 Think About

• Is the removed weight located to port or starboard of the centerline, and how does that direction compare to the original TCG’s direction? • When a weight is removed from the starboard side, does the ship’s center of gravity move toward port or toward starboard? Why? • After computing the shift GG', how do you algebraically combine it with the original TCG (0.5 ft to port) to get the final TCG and its direction?

✅ Before You Answer

• Confirm whether the denominator in your GG' calculation is the new displacement (W − w) rather than the original W. • Double-check the distance d between the original G and the weight: is it measured correctly from the centerline? • Verify the sign and direction of your final TCG: port vs starboard must match your arithmetic sign.