A non-symmetrical tank aboard a MODU...

Question 1 of 2707066636ee728f7522a1c5183f2

A non-symmetrical tank aboard a MODU contains 390 tons of ballast at a VCG of 9.85 feet. Ballast weighing 250 tons and a VCG of 12.0 feet is discharged. The vertical moments for the remaining ballast is __________.

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Question 1 of 27070

🔍 Key Concepts

• Vertical center of gravity (VCG) and how it relates to moment = weight × VCG • Effect of removing weight on total weight and total vertical moments • Distinguishing between total moment of original ballast, moment of discharged ballast, and moment of remaining ballast

💭 Think About

• First, how do you calculate the total vertical moment of the ballast that is originally in the tank using the given weight and VCG? • Next, how do you calculate the vertical moment of the ballast that is discharged using its given weight and VCG? • Once you know both of those moments, what mathematical operation gives you the moment of the remaining ballast in the tank?

✅ Before You Answer

• Be sure you use moment = weight × VCG for both the original ballast and the discharged ballast before doing any subtraction. • Verify that you subtract the correct weight and moment (discharged ballast) from the original totals to find the remaining values. • Check that your final answer is expressed in ft-long tons, matching the units in the answer choices.