A non-symmetrical tank aboard a MODU contains 390 tons of ballast at a VCG of 9.85 feet. Ballast weighing 250 tons and a VCG of 12.0 feet is discharged. The vertical moments for the remaining ballast is __________.
ā¢ Vertical center of gravity (VCG) and how it relates to moment = weight Ć VCG ā¢ Effect of removing weight on total weight and total vertical moments ā¢ Distinguishing between total moment of original ballast, moment of discharged ballast, and moment of remaining ballast
ā¢ First, how do you calculate the total vertical moment of the ballast that is originally in the tank using the given weight and VCG? ā¢ Next, how do you calculate the vertical moment of the ballast that is discharged using its given weight and VCG? ā¢ Once you know both of those moments, what mathematical operation gives you the moment of the remaining ballast in the tank?
ā¢ Be sure you use moment = weight Ć VCG for both the original ballast and the discharged ballast before doing any subtraction. ā¢ Verify that you subtract the correct weight and moment (discharged ballast) from the original totals to find the remaining values. ā¢ Check that your final answer is expressed in ft-long tons, matching the units in the answer choices.
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