A MODU displacing 28,000 long tons has a KG of 60 feet. A weight of 500 long tons is discharged from a VCG 150 feet. The change in KG is __________.
• KG (height of center of gravity) and how it changes when weights are added or removed • The formula for change of KG when a weight is discharged: ( \Delta KG = \frac{w \times (VCG - KG)}{W - w} ) (think conceptually: moment lost divided by new displacement) • Difference between using original displacement and new displacement in the denominator
• When you discharge (remove) a weight located above the ship’s KG, does KG move up or down? Why? • Should the total displacement in the denominator be the original displacement or the new displacement after discharge? How does that choice change your numerical result? • Estimate the size of the change: Is 500 LT a small or large fraction of 28,000 LT, and would you expect KG to change by a few tenths of a foot or by several feet?
• Compute the new displacement correctly: 28,000 LT − 500 LT before using it in your formula. • Use the correct moment removed: 500 LT × (150 ft − 60 ft), not just 500 × 150. • After you find ( \Delta KG \), check that your final change is a positive number in the correct direction (KG should move downward when a high weight is discharged).
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