A floating MODU displacing 20,000 long tons...

Question 1 of 2707066636ee728f7522a1c517b90

A floating MODU displacing 20,000 long tons with a VCG of 50 feet loads 100 long tons at 100 feet above the baseline and 200 long tons at 130 feet above the baseline. What is the new KG?

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Question 1 of 27070

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A floating MODU displacing 20,000 long tons with a VCG of 50 feet loads 100 long tons at 100 feet above the baseline and 200 long tons at 130 feet above the baseline. What is the new KG?

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🔍 Key Concepts

• Use the shift in center of gravity (KG) formula when weights are added: New KG = (Σ(W × KG))/ΣW • Remember that baseline is your reference for vertical centers, so use those heights as KG values for the added weights • Keep track of the original displacement and KG separately from the added weights, then combine them

💭 Think About

• How do you represent the original vessel’s vertical center of gravity (KG) in terms of moment (W × KG)? • When you add new weights at known heights, how do their moments affect the total moment and thus the new KG? • After summing all weights and all moments, what final division gives you the new KG?

✅ Before You Answer

• Be sure you are using long tons consistently for all weights • Confirm you have calculated three separate moments: original vessel, first added weight, second added weight • Double-check that you divide the total moment by the total weight to get the final KG