A floating jack-up with displacement of 15,000 kips has its LCG 106 feet aft of frame zero (AF0). If 200 short tons are loaded at 20 feet AF0 and 400 short tons are loaded 149 feet AF0, what is the new LCG?
• Longitudinal Center of Gravity (LCG) shifts when weights are added or removed • Use the moment = weight × distance concept to find total moments about frame zero • The new LCG is found by dividing total longitudinal moment by total displacement
• How do the added weights forward and aft of the original LCG affect the vessel’s overall center of gravity—do they move it forward, aft, or keep it the same? • What is the vessel’s total displacement after loading these weights, and what are the corresponding total longitudinal moments about frame zero? • Once you have the new total moment and total weight, what single calculation gives you the new LCG location?
• Convert all weights to the same units (be consistent: kips vs short tons) before summing • Make sure you calculate each added weight’s moment about frame zero correctly: ( M = W \times d ) • After computing the new LCG, compare its position to the original 106 ft LCG and ask: does the direction of shift make physical sense given where you loaded the cargo?
No comments yet
Be the first to share your thoughts!