A 30 HP electric motor is rotating shaft "A" at 300 rpm. What is the horsepower and rpm at shaft "B", if the efficiency of the spur gears is 67%? See illustration GS-0136.
⢠Gear ratios: For meshed gears, speed is inversely proportional to the number of teeth on each gear. ⢠Power and efficiency: Output horsepower = input horsepower à efficiency (expressed as a decimal). ⢠Direction of speed change when a large gear drives a small gear.
⢠First, decide whether the output horsepower at shaft B should be greater than, equal to, or less than 30 HP when the efficiency is 67%. What simple formula links these three values? ⢠Looking at the illustration, is shaft B attached to the larger gear or the smaller gear? When a large gear drives a smaller gear, does the smaller gear turn faster or slower than the large one? ⢠Use the relative size (or tooth count X vs. Y) to estimate the speed ratio between shaft A and shaft B, then apply that ratio to 300 rpm.
⢠Compute output power using HP_out = HP_in à efficiency and compare that with the choices (watch units and rounding). ⢠Confirm which gear (A or B) has more teeth, and therefore which shaft must have the higher rpm. ⢠Verify that your chosen answer matches both the expected horsepower from efficiency and the expected speed change from the gear size ratio.
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