Your vessel displaces 9,000 tons and has a...

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Question 1 of 2066636eec28f7522a1c51d104

Your vessel displaces 9,000 tons and has a KG of 21.2 feet. What will be the length of the remaining righting arm at an angle of inclination of 30? if the center of gravity shifts 2.6 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

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Question 1 of 20

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🔍 Key Concepts

• KN curve and GZ (righting arm) at 30° from the blue pages of the Stability Data Reference Book • Relationship between KG, KN, and GZ: GZ = KN − KG·sin(θ) (as tabulated/illustrated in the book • Effect of a transverse shift of G (2.6 ft) on creating a heeling arm that reduces the available righting arm

💭 Think About

• From the blue pages, how do you determine the ship’s original GZ at 30° for KG = 21.2 ft before any shift of G? • Once the center of gravity moves 2.6 ft transversely, how do you convert that shift into a heeling lever at 30° (what trigonometric function and what angle are involved?) • After you find both the original righting arm at 30° and the heeling arm caused by the shift, what mathematical operation combines them to give the remaining righting arm?

✅ Before You Answer

• Be sure you use the correct KG line (21.2 ft) and the correct angle (30°) in the blue pages when reading off GZ or KN. • Confirm that the 2.6‑ft shift of G is treated as GG₁, and that you are using the correct sine or cosine of 30° when finding its heeling lever. • After calculating the remaining GZ, check that your result is positive and of realistic magnitude (on the order of a few feet, not inches or tens of feet) before matching it to the closest multiple‑choice option.

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