Your vessel displaces 640 tons. The existing...

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Question 1 of 2066636eec28f7522a1c51d0f8

Your vessel displaces 640 tons. The existing deck cargo has center of gravity of 2.3 feet above the deck and weighs 18 tons. If you load 12 tons of ground tackle with an estimated center of gravity of 21 inches above the deck, what is the final height of the CG of the deck cargo?

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🔍 Key Concepts

• Center of gravity (CG) of combined weights and how to calculate it using moments • How to convert inches to feet so all distances are in the same unit • How adding heavier/lower cargo affects the overall CG height

💭 Think About

• First, write down the CG and weight of the existing deck cargo, then the CG and weight of the new ground tackle. How do you combine them? • Think about whether the ship’s total displacement (640 tons) is needed to find the deck cargo CG, or if you only need the weights that are part of the deck cargo. • Will the final combined CG be closer to 2.3 ft or 21 inches (~1.75 ft)? Which weight has more effect on where the final CG ends up?

✅ Before You Answer

• Make sure all vertical distances (2.3 ft and 21 inches) are in the same units before calculating. • Use the moment equation: Total moment = (weight 1 × CG 1) + (weight 2 × CG 2). Then divide by total deck cargo weight. • After you compute the final CG height, check if it is between the two original CG heights and closer to the one with greater weight.

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