Your vessel displaces 560 tons. The existing...

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Question 1 of 2066636eec28f7522a1c51d0ee

Your vessel displaces 560 tons. The existing deck cargo has a center of gravity of 4.5 feet above the deck and weighs 34 tons. If you load 10 tons of ground tackle with an estimated center of gravity of 2.8 feet above the deck, what is the final height of the CG of the deck cargo?

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Question 1 of 20

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🔍 Key Concepts

• Vertical center of gravity (KG) and how combined centers of gravity are calculated using moments • How to compute the moment of each weight about the deck (weight × vertical distance) • Using a weighted average of the heights based on each weight to find the new combined CG

💭 Think About

• How do you compute the total moment of the original deck cargo about the deck? What about the new ground tackle? • Once you have the total combined moment and total combined weight of the deck cargo, what formula relates these to the new combined CG height? • Does adding a lower CG weight (2.8 ft) to a higher CG weight (4.5 ft) move the overall CG up or down, and by about how much, given the relative weights?

✅ Before You Answer

• Be sure you are only combining the weights and CGs of the deck cargo items, not the entire vessel displacement for this calculation. • Double-check that you added the weights correctly before computing the new CG (34 tons + 10 tons). • Verify that you computed each moment correctly (weight × CG height), then divided the total moment by the total weight to get the final CG.

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